WebA circle has a measure of 360 degrees. Dividing it by 2, the quotient will be 180 which is also the measure of AB. AB is also a semicircle. AE = 82 *AE is an intercepted arc of AOE. AOE is a central angle because its vertex is the center of the circle. WebTangent CD intersects with circle A at point D, tangent CE intersects with circle A at point E, angle ECD is on the exterior of circle A, and angle DAE has a vertex on the center of circle …

(09.01 MC) Lines CD and DE are tangent to circle A as shown below:

WebLine segment TS is tangent to circle O at point N. If the measure of QNT is 74°, what is the measure of QNP? 148° Line segment BD is a diameter of circle E. What is the measure of arc BC? 78° What must be the length of ZY in order for ZY to be tangent to circle X at point Y? 15 units. What is the measure of CED? 212° In circle T, ∠PTQ ≅ ... WebWith a radius of 18, the circumference is C=2πr=36π. So the arc is 14π/36π of the circumference or 7/18 of a circle. In degrees, 7/18*360 = 140 degrees for arc BA, and since you already know 76 degrees, 140-76=64 degrees. How are you getting 144 degrees? 1 comment ( 2 votes) murarisettigayatri20 2 years ago chinese keyboard smart phone

Circles- Part 1 Unit Test 96% - Subjecto.com

WebCircle A with angle BAD measuring 148 degrees, points B, C, and D lie on Circle A. a. 96° b. 22° c. 52° d. 148° 3, Lines CD and DE are tangent to circle A: If CE is 98°, what is the … WebIn circle a shown below, the measure of ∠bad is 148°: if m bc is 105°, what is m cd? answers 74 148 43 31. Answers: 3 Show answers ... WebIn the given figure, O is the center of the circle. ∠OAB and ∠OCB are 30o and 40o respectively. Find ∠AOC Show your steps of working. Solution: Firstly, let’s join AC. And, let ∠OAC = ∠OCA = x [Angles opposite to equal sides are equal] So, ∠AOC = 180 o – 2x Also, ∠BAC = 30 o + x ∠BCA = 40 o + x Now, in ∆ABC grandpa i been thinking bout you lately